Apa jawaban dari soal diatas?

jawabannya 1/6
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[tex] \frac{lim}{x - > 9} = \frac{ \sqrt{x} - 3}{x - 9} \times \frac{ \sqrt{x} + 3 }{ \sqrt{x} + 3} = \frac{x - 9}{(x - 9)( \sqrt{x} + 3} = \frac{1}{ \sqrt{x} + 3 } = \frac{1}{ \sqrt{9} + 3 } = \frac{1}{3 + 3} = \frac{1}{6} [/tex]