bisa bantu no.6 sama cara nya

[tex]3 + 4y = 11 \\ 4y = 11 - 3 \\ 4y = 8 \\ y = 2 \\ \\ 5 + 2z = 4 \\ 2z = 4 - 5 \\ 2z = - 1 \\ z = \frac{ -1 }{2} \\ \\ 2x + 6y + 2z = 12 \\ 2x + 6(2) + 2( \frac{ - 1}{2} ) = 12 \\ 2x + 12 - 1 = 12 \\ 2x + 11 = 12 \\ 2x = 12 - 11 \\ 2x = 1 \\ x = \frac{1}{2} \\ \\ x + y + z = \frac{1}{2} + 2 + \frac{ - 1}{2} = 2[/tex]
maaf ya kalo salah:)))