pada gambar tersebut diket ED=12cm AE=15 cm BE= 8cm dan DC=16 cm keliling sudut ABC adalah.tolong kak

[tex] {ad}^{2} = {15}^{2} - {12}^{2} \\ {ad}^{2} = 225 - 144 \\ {ad}^{2 } = 81 \\ ad = \sqrt{81 = 9} [/tex]

[tex] {ec}^{2} = {12}^{2} + {16}^{2} \\ {ec}^{2} = 144 + 256 \\ {ec}^{2} = 400 \\ ec = \sqrt{400} = 20[/tex]

[tex] {ab}^{2} = {15}^{2} + {8}^{2} \\ {ab}^{2} = 225 + 64 \\ {ab}^{2} = 289 \\ ab = \sqrt{289} = 17[/tex]

keliling = ab + bc + ac
keliling = ab + (be + ec) + (ad + dc)
keliling = 17 + (20+8) + (16+9)
keliling = 17 + 28 + 25
keliling= 70 cm

jawabannya b