Diketahui f(x) =2x-1 / x+1, g (x) =x^2-1, dan h(x) =3x+5 Tentukan: (h^-1 o f^-1)(x)

FungSI KompoSISI
---------------------------


       f (x) = (2x - 1)/(x + 1)
           y = (2x - 1)/(x + 1)
   xy + y = 2x - 1
  xy - 2x = -1 - y
 x (y - 2) = -1 - y
           x  = (-1 -y)/(y - 2)
   f^-1 (x) = (-1 - x)/(x - 2)


h (x)      = 3x + 5
     y      = 3x + 5
y - 5      = 3x
(y - 5)/3 = x
(x - 5)/3 = h^-1 (x)


(f^-1 o h^-1) (x) = f^-1(h^-1) (x)
                          = (-1 - ((x - 5)/3))/((x -5)/3) - 2)
                          = (-3x + 6)/(3x - 33)



Semoga Membantu!!!