Diketahui f(x) =2x-1 / x+1, g (x) =x^2-1, dan h(x) =3x+5 Tentukan: (f^-1 o h^-1)(x)

[tex] {f}^{ - 1} (x) = \frac{ - x - 1}{x - 2} \\ {h}^{ - 1} (x) = \frac{x - 5}{3} \\ ( {f}^{ - 1} o {h}^{ - 1} )(x) = \frac { - ( \frac{x - 5}{3}) - 1 }{ \frac{x - 5}{3} - 2} = \frac{ \frac{ - x + 2}{3} }{ \frac{x - 11}{3} } = \frac{2 - x}{x - 11} [/tex]

FungSI KompoSISI
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       f (x) = (2x - 1)/(x + 1)
           y = (2x - 1)/(x + 1)
   xy + y = 2x - 1
  xy - 2x = -1 - y
 x (y - 2) = -1 - y
           x  = (-1 -y)/(y - 2)
   f^-1 (x) = (-1 - x)/(x - 2)


h (x)      = 3x + 5
     y      = 3x + 5
y - 5      = 3x
(y - 5)/3 = x
(x - 5)/3 = h^-1 (x)


(f^-1 o h^-1) (x) = f^-1(h^-1) (x)
                          = (-1 - ((x - 5)/3))/((x -5)/3) - 2)
                          = (-3x + 6)/(3x - 33)



Semoga Membantu!!!