Matematika

Pertanyaan

nmr 29 , 30 makasii
nmr 29 , 30 makasii

2 Jawaban

  • Penyelesaian :
    Nomor 29
    Volume kubus => S × S × S

    Volume kubus a
    = 15 cm × 15 cm × 15 cm
    = 3375 cm^3

    Volume kubus b
    = 18 cm × 18 cm × 18 cm
    = 5832 cm^3

    Selisih volume
    = 5832 cm^3 - 3375 cm^3
    = 2457 cm^3
    Opsi => A

    Nomor 30
    Luas permukaan tabung
    = 2 × phi × r × ( r + t )
    = 2 × 22/7 × 14 × ( 14 + 25 )
    = 88 × 39
    = 3432 cm^2
    Opsi => D
  • 29. volume kubus 1 = 15×15×15=3375
    volume kubus 2= 18×18×18= 5832
    selisih= 5832-3375=2457 A

    30. luas permukaan= 2×phi×r(r+t)
    = 2×22/7×14(14+25)
    = 2×22/7×14×39
    =3432 D