nmr 29 , 30 makasii
Matematika
Elvitaa98
Pertanyaan
nmr 29 , 30 makasii
2 Jawaban
-
1. Jawaban ferlitajihan
Penyelesaian :
Nomor 29
Volume kubus => S × S × S
Volume kubus a
= 15 cm × 15 cm × 15 cm
= 3375 cm^3
Volume kubus b
= 18 cm × 18 cm × 18 cm
= 5832 cm^3
Selisih volume
= 5832 cm^3 - 3375 cm^3
= 2457 cm^3
Opsi => A
Nomor 30
Luas permukaan tabung
= 2 × phi × r × ( r + t )
= 2 × 22/7 × 14 × ( 14 + 25 )
= 88 × 39
= 3432 cm^2
Opsi => D -
2. Jawaban irma592
29. volume kubus 1 = 15×15×15=3375
volume kubus 2= 18×18×18= 5832
selisih= 5832-3375=2457 A
30. luas permukaan= 2×phi×r(r+t)
= 2×22/7×14(14+25)
= 2×22/7×14×39
=3432 D