Tolong jawab no 4dan5
Matematika
novalisa205
Pertanyaan
Tolong jawab no 4dan5
1 Jawaban
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1. Jawaban Melya20
4. 78cm
Keliling [tex] \frac{1}{2} [/tex] lingkaran = [tex] \frac{1}{2} [/tex] × [tex]2 \pi r[/tex]
= [tex] \frac{1}{2} [/tex] × 2 × [tex] \frac{22}{7} [/tex] × 7cm
= [tex] \frac{1}{2} [/tex] × 44cm
= 22cm
Kelililng Persegi Panjang = 2 (p+l)
= 2 (24cm+14cm)
= 2 (38cm)
= 76cm
Keliling Bangun No.4 = 22cm + 76cm = 98cm
5. Kelililng Persegi Panjang = 2 (p+l)
= 2 (20cm + 10cm)
= 2 (30cm)
= 60cm
Keliling Segitiga = a + b + c
Cari dulu c nya
c = [tex] \sqrt{ a^{2} + b^{2} } = \sqrt{ 5cm^{2} + 12cm^{2} } = \sqrt{ 25cm + 144cm } = \sqrt{169} = 13cm[/tex]
= 10cm + 12 cm + 13cm = 35cm
Keliling bangun No.5 = 60cm + 35cm = 95cm