Matematika

Pertanyaan

Tolong jawab no 4dan5
Tolong jawab no 4dan5

1 Jawaban

  • 4. 78cm
        Keliling [tex] \frac{1}{2} [/tex] lingkaran = [tex] \frac{1}{2} [/tex] × [tex]2 \pi r[/tex]
        = [tex] \frac{1}{2} [/tex] × 2 × [tex] \frac{22}{7} [/tex] × 7cm
        = [tex] \frac{1}{2} [/tex] × 44cm
        = 22cm

       
    Kelililng Persegi Panjang = 2 (p+l)
        = 2 (24cm+14cm)
        = 2 (38cm)
        = 76cm
        Keliling Bangun No.4 = 22cm + 76cm = 98cm


    5.
    Kelililng Persegi Panjang = 2 (p+l)
        = 2 (20cm + 10cm)
        = 2 (30cm)
        = 60cm

        Keliling Segitiga = a + b + c
        Cari dulu c nya
        c =  [tex] \sqrt{ a^{2} + b^{2} } = \sqrt{ 5cm^{2} + 12cm^{2} } = \sqrt{ 25cm + 144cm } = \sqrt{169} = 13cm[/tex]
        = 10cm + 12 cm + 13cm = 35cm
        Keliling bangun No.5 = 60cm + 35cm = 95cm