1.122°F=.....°K 2.44°R=.....°K 3.0°K=.....°C
Fisika
LizkyM
Pertanyaan
1.122°F=.....°K
2.44°R=.....°K
3.0°K=.....°C
2.44°R=.....°K
3.0°K=.....°C
1 Jawaban
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1. Jawaban Nisasageyo
1)5/9 x (122-32)
5/9 x 90 = 50°C
50+ 273 = 323°K
2)5/4 x 44 = 55
55+273 =328°K
3)0-273 = -273°C