Tunjukan bahwa 1 + tan^2 45° = sec^2 45°

Jawaban ada dilampiran

[tex] {sin}^{2} 45^{0} + {cos}^{2} {45}^{0} = 1 \\ = > dibagi \: {cos}^{2} \ {45}^{0} \\ = > \: \frac{ {sin}^{2} \ {45}^{0} }{ {cos}^{2} {45}^{0} } + \frac{ {cos}^{2} {45}^{0} }{ {cos}^{2} \ {45}^{0} } = \frac{1}{ {cos}^{2} {45}^{0} } \\ = > {tan}^{2} {45}^{0} + 1 = {sec}^{2} {45}^{0} \: (terbukti)[/tex]