Carilah n jika (dalam deret geometri) 2+4+8+..+2^n=510

Sn = 510 Ket : ^n = pangkat n
a = 2
r = 4/2
= 2

Sn = a(r^n - 1)
r - 1
510 = 2(r^n - 1)
510 = 2r^n - 2
2r^n = 510+2
r^n = 512/2
r^n = 256
r^n = 16²
r^n = 2⁸

subtisusi nilai r ke -> r^n = 2⁸
2^n = 2⁸
n = 8
jadi nilai n = 8