Matematika

Pertanyaan

3log25 × 5log81 - 4log2
__________________
3log36 - 3log4

1 Jawaban

  • Kelas 10 Matematika
    Bab Logaritma

    (³log 25 . ⁵log 81 - ⁴log 2)/(³log 36 - ³log 4)
    = (³log 81 . ⁵log 25 - ⁴log 4^(1/2)) / (³log (36/4))
    = (³log 3⁴ . ⁵log 5² - 1/2 . ⁴log 4) / (³log 3²)
    = (4 . 2 - 1/2) / 2
    = (16 - 1)/4
    = 15/4

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