tolong ya kakak di jawab...

1. Panjang lintasan = keliling roda × 200
[tex] = \pi \times d \times 200 \\ = 3.14 \times 25 \times 200 \\ = 628 \times 25 \\ = 15700 \: cm[/tex]
2. Total biaya = (luas persegi - luas lingkaran) × Rp. 1500
[tex]luas \: persegi - luas \: lingkaran \\ = (s \times s) - ( \frac{1}{4} \times \pi \times d \times d) \\ = (30 \times 30) - ( \frac{1}{4} \times 3.14 \times 25 \times 25) \\ = 900 - ( \frac{1}{4} \times 3.14 \times 625) \\ = 900 - ( \frac{1}{4} \times 1962.5) \\ = 900 - 490.625 \\ = 409.375 \: {cm}^{2} [/tex]
Total biaya = 409.375 × 1500
=614062. 5
Total biaya = Rp 614.062,5