tolong!!!! jawab ya nb : yang ngawur saya hapus jawabannya

Rumus Umum:
[tex]\displaystyle \frac{y-y_1}{y_2-y_1}=\frac{x-x_1}{x_2-x_1}[/tex]

Kiri:
[tex]\displaystyle \frac{y-y_1}{y_2-y_1}=\frac{x-x_1}{x_2-x_1} \\ \frac{y-(-4)}{6-(-4)}=\frac{x-(-1)}{2-(-1)} \\ \frac{y+4}{10}=\frac{x+1}{3} \\ 3(y+4)=10(x+1) \\ 3y+12=10x+10 \\ 10x-3y-2=0[/tex]

Kanan:
[tex]\displaystyle \frac{y-y_1}{y_2-y_1}=\frac{x-x_1}{x_2-x_1} \\ \frac{y-3}{-5-3}=\frac{x-1}{8-1} \\ \frac{y-3}{-8}=\frac{x-1}{7} \\ 7(y-3)=-8(x-1) \\ 7y-21=-8x+8 \\ 8x+7y-29=0[/tex]