kalo ada yang bisa tolong ya

1. HCl -> H+ + Cl-
0,03M
[H+] = 0,03 M = 3x10^-2
pH = - log[H+] = - log3x10^-2 = 2 - log3

2. Ca(OH)2 -> Ca^2+ + 2OH-
[OH-] = 2x0,02 = 0.04 = 4x10^-2
pOH = - log[OH-] = - log 4x10^-2 = 2 - log4
pH = 14 - (2 - log4) = 12 + log4

3. HF -> H+ + F-
[H+] = √Ka x M = √0.7x10^-6 x 0.07 = √0.049 x 10^-6 = √49 x 10^-9 = 7 x 10^-4.5
pH = - log [H+] = - log 7x10^-4.5 = 4.5 - log7

4. NH4OH -> NH4+ + OH-
[OH-] = √Kb x M = √1.8x10^-5 x 0.05 = √0.09 x 10^-5 = √9 x 10^-7 = 3 x 10^-3.5
pOH = - log [OH-] = - log 3 x 10^-3.5 = 3.5 - log3
pH = 14 - (3.5 - log3) = 10.5 + log3

Maaf kalau membingungkan^^