Diketahui ³log6 = p dan ³log2 = q. Nilai ²⁴log288 = ....

²⁴log 288
=³log 288 / ³log 24
=(³log 3²×2^5) / (³log 3 × 2³)
=(2 ³log3 + 5 ³log2) / (³log 3 + 3 ³log 2)
=(2+5q)/(1+3q)

²⁴log 288
=³log 288 / ³log 24
=(³log 6²×2³) / (³log 6 × 2²)
=(2 ³log6 + 3 ³log2) / (³log6 + 2 ³log2)
=(2p+3q)/(p+2q)